WIP: day5: Complete second puzzle

This currently reports correct numbers for the non-diagonal case, but
incorrect ones for the diagonal case.

The true number lies somewhere between 17880 (probably far too low)
and 23062, but all tests I can come up with intersect correctly so I
don't understand how the second number is wrong.
main
Tristan Daniël Maat 2021-12-08 00:37:26 +00:00
parent b51cfbffc0
commit 0a5ed079ac
Signed by: tlater
GPG Key ID: 49670FD774E43268
1 changed files with 115 additions and 42 deletions

View File

@ -1,7 +1,27 @@
import Data.List (nub, tails)
import Debug.Trace (traceShow, traceShowId)
import Parsing (splitByString)
type Line = ((Int, Int), (Int, Int))
type Vector = (Int, Int)
fromLine :: Line -> Vector
fromLine ((x1, y1), (x2, y2)) = (x2 - x1, y2 - y1)
vCross2D :: Vector -> Vector -> Int
vCross2D (x1, y1) (x2, y2) = x1 * y2 - y1 * x2
vSubtract :: Vector -> Vector -> Vector
vSubtract (x1, y1) (x2, y2) = (x2 - x1, y2 - y1)
vAdd :: Vector -> Vector -> Vector
vAdd (x1, y1) (x2, y2) = (x1 + x2, y1 + y2)
sMult :: Int -> Vector -> Vector
sMult s (x, y) = (s * x, s * y)
sDiv :: Int -> Vector -> Vector
sDiv s (x, y) = (x `quot` s, y `quot` s)
main :: IO ()
main = do
@ -9,56 +29,92 @@ main = do
let
vents = parseVents input
putStrLn (show (solution1 vents))
putStrLn (show (solution2 vents))
solution1 :: [Line] -> Int
solution1 = length . nub . intersectAll . filterDiagonal
intersectAll :: [Line] -> [(Int, Int)]
solution2 :: [Line] -> Int
solution2 = length . nub . traceShowId . intersectAll
intersectAll :: [Line] -> [Vector]
intersectAll =
flatten . (map intersectOne) . (combinations 2)
where
intersectOne :: [Line] -> [(Int, Int)]
intersectOne [] = []
intersectOne (vent:others) = flatten (map (intersect vent) others)
intersectOne :: [Line] -> [Vector]
intersectOne [] = []
-- "other" is a vector of size 1, so (head other) is fine
intersectOne (vent:other) = intersect vent (head other)
intersect :: Line -> Line -> [Vector]
intersect l1@(p, _) l2@(q, _)
-- Colinear
| rsAngle == 0 && qprAngle == 0 =
intersect1D l1 l2
-- Parallel, non-intersecting
| rsAngle == 0 && qprAngle /= 0 =
[]
-- Intersecting
| rsAngle /= 0
&& qpsAngle `dividesUnit` rsAngle
&& qprAngle `dividesUnit` rsAngle =
[intersection]
-- Non-parllel, non-intersecting
| otherwise =
[]
intersect :: Line -> Line -> [(Int, Int)]
intersect ((x1, y1), (x1', y1')) ((x2, y2), (x2', y2'))
-- Colinear - In these cases, we may have multiple intersections
| all (== x1) [x1', x2, x2'] =
(map (\y -> (x1,y)) (intersect1D (sortedTuple (y1, y1')) (sortedTuple (y2, y2'))))
| all (== y1) [y1', y2, y2'] =
(map (\x -> (x,y1)) (intersect1D (sortedTuple (x1, x1')) (sortedTuple (x2, x2'))))
-- Not colinear - We can find out if these intersect by simply
-- checking whether the second line goes through the
-- horizontal/vertical range of the first (whichever line the first
-- segment lives on)
| (x1 == x1' && y2 == y2') =
if (min x2 x2') <= x1 && (max x2 x2') >= x1 && (min y1 y1') <= y2 && (max y1 y1') >= y2
then
[(x1,y2)]
else
[]
| (y1 == y1' && x2 == x2') =
if (min y2 y2') <= y1 && (max y2 y2') >= y1 && (min x1 x1') <= x2 && (max x1 x1') >= x2
then
[(x2,y1)]
else
[]
-- In all other cases, we consider the lines not to intersect, since
-- diagonal lines are out of scope
| otherwise = []
where
sortedTuple :: (Int, Int) -> (Int, Int)
sortedTuple (a, b)
| a > b = (b, a)
| otherwise = (a, b)
intersect1D :: (Int, Int) -> (Int, Int) -> [Int]
intersect1D (a, b) (c, d) =
let
start = max a c
end = min b d
in
[start..end]
r = fromLine l1
s = fromLine l2
rsAngle = r `vCross2D` s
qprAngle = (p `vSubtract` q) `vCross2D` r
qpsAngle = (p `vSubtract` q) `vCross2D` s
intersection = q `vAdd` (rsAngle `sDiv` (qprAngle `sMult` s))
intersect1D :: Line -> Line -> [Vector]
intersect1D l1@((x1, y1), (x1', y1')) l2@((x2, y2), (x2', y2'))
-- Note that when we're here all cases are colinear (and perhaps
-- overlapping). This means that the lines must occupy the same
-- axes, and we only need to check the orientation of one.
-- Diagonal lines; if these overlap, they overlap in a range
-- given by the overlap in their projections on the x and y axis
| isDiagonal l1 = zip (overlap (x1, x1') (x2, x2')) (overlap (y1, y1') (y2, y2'))
-- Others overlap in the range where their respective x/y axis
-- projection overlaps, and the other doesn't change
| isHorizontal l1 = zip (repeat x1) (overlap (y1, y1') (y2, y2'))
| isVertical l1 = zip (overlap (x1, x1') (x2, x2')) (repeat y1)
where
isDiagonal :: Line -> Bool
isDiagonal ((x, y), (x', y')) = x /= x' && y /= y'
isHorizontal :: Line -> Bool
isHorizontal ((x, y), (x', y')) = x == x'
isVertical :: Line -> Bool
isVertical ((x, y), (x', y')) = y == y'
overlap :: Vector -> Vector -> [Int]
overlap (a, b) (c, d) =
let
(a', b') = sortedTuple (a, b)
(c', d') = sortedTuple (c, d)
start = max a' c'
end = min b' d'
in
[start..end]
where
sortedTuple :: Vector -> Vector
sortedTuple (a, b)
| a > b = (b, a)
| otherwise = (a, b)
-- Whether a division will give a number 0 <= x <= 1
dividesUnit :: Int -> Int -> Bool
dividesUnit a b
| a == 0 = True
| a > 0 = a <= b
| a < 0 = a >= b && b < 0
filterDiagonal :: [Line] -> [Line]
filterDiagonal = filter (not . isDiagonal)
@ -107,6 +163,7 @@ testInput1 = unlines [
]
test1 = solution1 (parseVents testInput1)
test2 = solution2 (parseVents testInput1)
testIntersect1 = intersect ((0, 0), (0, 5)) ((0, 2), (0, 4)) == [(0, 2), (0, 3), (0, 4)]
testIntersect2 = intersect ((0, 0), (0, 5)) ((0, 5), (0, 6)) == [(0, 5)]
@ -120,6 +177,13 @@ testIntersect9 = intersect ((1, 0), (1, 5)) ((2, 2), (4, 2)) == []
testIntersect10 = intersect ((9, 4), (3, 4)) ((7, 0), (7, 4)) == [(7, 4)]
testIntersect11 = intersect ((2, 2), (2, 1)) ((3, 4), (1, 4)) == []
testIntersect12 = intersect ((0, 9), (5, 9)) ((7, 0), (7, 4)) == []
testIntersect13 = intersect ((9, 4), (3, 4)) ((3, 4), (1, 4)) == [(3, 4)]
testIntersect14 = intersect ((0, 0), (1, 1)) ((1, 1), (2, 2)) == [(1, 1)]
testIntersect15 = intersect ((0, 0), (3, 3)) ((1, 1), (3, 3)) == [(1, 1), (2, 2), (3, 3)]
testIntersect16 = intersect ((0, 0), (3, 3)) ((4, 4), (8, 8)) == []
testIntersect17 = intersect ((0, 1), (1, 2)) ((1, 2), (3, 4)) == [(1, 2)]
testIntersect18 = intersect ((0, 1), (3, 4)) ((1, 2), (3, 4)) == [(1, 2), (2, 3), (3, 4)]
testIntersect19 = intersect ((0, 1), (3, 4)) ((0, 0), (3, 3)) == []
testIntersect =
all (== True) [
@ -131,5 +195,14 @@ testIntersect =
testIntersect6,
testIntersect7,
testIntersect8,
testIntersect9
testIntersect9,
testIntersect10,
testIntersect11,
testIntersect12,
testIntersect13,
testIntersect14,
testIntersect15,
testIntersect16,
testIntersect17,
testIntersect18
]